Ablock of mass m 13 kg slides along a horizontal surface (with friction, μ,-0.31) a distance d= 2.55 m before striking a second block of mass m2-9.75 kg.
the first block has an initial velocity of v 7.75 m/s.

randomized variables :
m1 = 13 kg
m2 = 9, 75 kg
μ,-0.31
d-2.55 m
v=7.75m/s m2

a) assuming that block one stops after it collides with block two, what is block two's velocity after impact in m/s?
numeric: a numeric value is expected and not an expression.

(b) how far does block two travel, d in meters, before coming to rest after the collision?
numeric: a numeric value is expected and not an expression.

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.

connectedness in handwriting analysis is a useful tool in establishing the writer’s method of thinking and its perception in where he/she fits in to the environment around him in the social sense. in addition, the more connected the writing of an individual, the more he/she is flexible and single minded.

the correct answer is "inertia"