A25 kg block is held against a compressed spring and then the spring is allowed to decompress giving the block a velocity. the block then slides to the right on a horizontal frictionless surface and then up a frictionless incline.
find the maximum height that the block reaches if the incline is 19.5 ∘ . all surfaces are frictionless, the spring constant is 1300 n/m and the initial spring compression is 26.4cm.

h=18.05 cm

Explanation:

Given that

m= 25 kg

K= 1300 N/m

x=26.4 cm

θ= 19.5 ∘

When the block just leave the spring then the speed of block = v m/s

From energy conservation

By putting the values

v=1.9 m/s

When block reach at the maximum height(h) position then the final speed of the block will be zero.

We know that

By putting the values

h=0.1805 m

h=18.05 cm

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