Refrigerant-134a enters the evaporator coils placed at the back of the freezer section of a household refrigerator at 100 kpa with a quality of 20 percent and leaves at 100 kpa and −26°c. if the compressor consumes 600 w of power and the cop of the refrigerator is 1.2, determine (a) the mass flow rate of the refrigerant and (b) the rate of heat rejected to the kitchen

The answer is mean don't know

My answer would be letter c: exceed federal standards. for example: buying a tank is legal in the state of alabama (figuratively speaking) but it is considered illegal according to federal law. federal laws will always override state laws.

A) the moment of inertia is given by i = mr^2 here m = 0.25 and r = 0.5. i = 0.25 * (0.5)^2 = 0.0625. b) i = 9.74 * 10^(37) and mass = 5.98 * 10^(24) so r^2 = i/m = 9.74 * 10^(37)/5.98 * 10^(24) = 1.628 * 10^(37 - 24) = 1.628 * 10^(13) r = √ 1.628 * 10^(13) = 4034848.200 c) since angular momentum is the product of moment of inertia and angular velocity, a = i * v; but i = mr^2 = 2 * 0.6^2 = 0.72 so a = 0.72 * 1.1 = 0.792. if she pulls her hand in 0.15 m. the new radius = 0.6 - 0.15 = 0.45. v = angular momentum/ radius = 0.792/ 0.45 = 1.76