Aglider airplane is coasting horizontally when a very heavy object suddenly falls out of it. as a result of dropping this object and assuming there is no air resistance, a) the glider’s speed will first increase, then decrease. b) the glider’s speed will first decrease, then increase. c) the glider’s speed will increase. d) the glider’s speed will decrease. e) the glider’s speed will remain the same as it was.

To solve the problem it is simply necessary to apply the concepts related to the kinematic equations of motion and Newton's second law.

Newton states that Force is proportional to mass and acceleration, so

We know that in the absence of air resistance, in a sum of forces on the Glider there would be no horizontal component. In this way there would only be two forces, the lifting force and the force caused by the total weight of the Glider. By decreasing the weight the variation that would exist is clearly in its vertical stability. As regards speed or acceleration, they will remain the same. Recall that the acceleration is the change of speed, and in the absence of a force that modifies this in the horizontal component, then the balance will remain there and the speed will remain constant. There is no force that generates a change in its horizontal component and that can affect drag or thrust.

The correct answer is, E) The glider's speed will remain the same as it was

im not to sure what it is

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz