Vertically polarized light is to be passed through a sequence of three polarizing filters. the direction of the polarization axis for each filter is indicated by lines drawn parallel to the axis. one filter is oriented so that its polarization axis is vertical, another is horizontal, and the third is at an angle between horizontal and vertical. place the three polarizers from left to right in the order that maximizes the amount of transmitted light.

Vertical  -- angle ---    horizontal

Explanation:

The intensity transmitted by a polarized is given by the expression

        I = I₀ cos² θ

Where tes is the angle between the polarization of light and the direction of polarization.

From this expression it is observed that if the angle is zero (parallel) the transmission is maximum and if in the angle it is 90 ° (perpendicular) the transmission is zero.

With these arguments we will analyze the three polarizers placements.

The light has an initial vertical polarization, so that the first possible polarizer is transmitted, it must be parallel, bone with vertical polarization

It is second polarizer must have some angle so that the light that comes out has vertical and horizontal polarization

Finally, the third polarizer must be horizontal for the horizontal second polarizer component to be transmitted.

Consequently the order is

Vertical  -- angle ---    horizontal

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).