You are making a frame of uniform width for a picture that is to be displayed at the local museum. the picture is 4 feet tall and 3 feet wide. the museum has allcoated 30 square feet of wall space to display the picture. what should the width of the frame be in order to use all of the allocated space?

1 feet

Explanation:

Frame width = x

The length of the frame will be

(bottom and top that is why x is added twice)

The width of the frame will be

Area is given by

Solving the above equation we get

Hence width of the frame is 1 ft

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.