A4 kg body is traveling at 3 m/s with no external force acting on it. at a certain instant an internal explosion occurs, splitting the body into two chunks of 2 kg mass each. the explosion gives the chunks an additional 18 j of kinetic energy. neither chunk leaves the line of original motion. determine the speed and direction of motion of each of the chunks after the explosion.

Answer

given,

mass of body = 4 Kg

travelling at speed = 3 m/s

exploded into two fragments of equal mass i.e. = 2 Kg

energy after collision increases by 18 J

original kinetic energy

KE = 18 J

energy increases after collision = 18 J

total energy = 36 J

now,

using conservation of momentum

m₁v₁ + m₂v₂ = MV

2 v₁ + 2 v₂ = 4 x 3

v₁ + v₂ = 6-------------(1)

squaring both side in the above equation

v₁² + v₂² + 2v₁v₂ = 36

72 + 2v₁v₂ = 36

v₁v₂ = -18-------(2)

putting value of equation (1) in (2)

v₁ (-18 - v₁) = 6

-18 v₁ - v₁² = 6

v₁² + 18 v₁ + 6 = 0

on solving the above equation we get

v₁ = -0.34 m/s

putting value of v₁ in equation (1)

v₂ = 6 + 0.34

v₂ = 6.34 m/s

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.