Force f⃗ =−10j^n is exerted on a particle at r⃗ =(7i^+5j^)m. part a what is the torque on the particle about the origin?

The torque on the particle about the origin is

The formula for calculating the torque is expressed as:

F is the force applied

r is the radius of the particle;

Given the following parameters

Substitute the given parameter into the formula:

According to cross product,

Taking the cross product of the force and the radius is

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Torque,

Explanation:

It is given that,

Force acting on the particle,

Position of the particle,

We need to find the torque on the particle about the origin. It is equal to the cross product of position and the force. Its formula is given by :

The cross product of vectors is given by :

or

So, the torque on the particle about the origin . Hence, this is the required solution.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m