A5.0-kg box rests on a horizontal surface. the coefficient of kinetic friction between the box and surface is μk=0.50. a horizontal force pulls the box at constant velocity for 10 cm. find the work done by (a) the applied horizontal force, (b) the frictional force, and (c) the net force.

Explanation:

Given

mass of box

coefficient of kinetic Friction

Box is moving with constant velocity therefore net Force on object is zero

Force applied=Frictional Force

Force applied

(a)work done by applied Force

(b)Work done by Friction force

(c)Total Work done =work done by Force+Work done by Frictional Force

i think the answer is a, hope this is right, that would be my best guess.