Submarine a and submarine b are heading
towards each other. they are both moving at a
steady speed of 5mls. submarine a produces
a pulse of sound to detect submarine b. the
sound is produced when the distance between
the two submarines was exactly 10 km.
the speed of sound in water is 1500 mls.
calculate the distance between submarine a
and submarine b when submarine a recieves
the echo reflected by submarine b.

The distance between the submarine is, d = 9933.3 m

Explanation:

Given data,

The speed of the submarine A and B, v  = 5 m/s

Submarine A produces  a pulse of sound to detect B at a distance, d = 10 km

                                                                                                          = 10000 m

The speed of sound in water is, V = 1500 m/s

The time period to receive echo is given by the formula,

                                                      t = d / v

                                                        = 10000 / 1500

                                                        = 6.67 s

The distance between the submarine is given by the relation

                                                    d = 10000 - 2(v x t)

                                                       = 10000 - 2(5 x 6.67)

                                                       = 9933.3 m

Hence, the distance between the submarine is, d = 9933.3 m

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

hope this ! ~

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day