Alarge beaker of water is placed on a scale, and the scale reads 40 n. a block of wood with a weight of 10 n is then placed in the beaker. it floats with exactly half of its volume submerged. assuming that none of the water spilled out of the beaker when the block was added, what does the scale read now? a. 40 nb. 45 nc. 50 nd. none of the above.

50 N

Explanation:

Given

Initially scale reads 40 N

a block of wood with weight 10 N is placed in beaker

Now the scale will read 50 N as it has bear the weight of both water and wood  because no water is spilled out of beaker and wood is also present .

Total reading on scale =40+10 =50 N

Although effective weight of wood be less as buoyancy is acting on it.

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i think the answer is a and b

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