In a two-slit experiment, the slit separation is 3.00 × 10-5 m. the interference pattern is recorded on a flat screen-like detector that is 2.00 m away from the slits. if the seventh bright fringe on the detector is 10.0 cm away from the central fringe, what is the wavelength of the light passing through the slits? (the central bright fringe is zeroth one).

To solve this problem, the concepts related to destructive and constructive Interference of light spot and dark spot are necessary.

By definition in the principle of superposition, light interference is defined as

Where,

d = Separation of the two slits

R = Distance from slit to screen

m= Any integer, which represents the repetition of the spectrum. The order of m equal to 1,2,3,4,5 represent bright bands and the order of m equal to 1.5,2.5,3.5 represent the dark bands.

Y = Distance from central spot to fringe.

Re-arrange the equation to find \lambda we have that

Our values are gives according the problem as,

m = 7 (The seventh bright fringe)

R = 2m

Therefore the wavelength of the light passing through the slits is 214nm

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

no sign of dia of fuel cell