In the second half of part i of refraction lab we are looking at the second air/glass boundary. from the law of alternate interior angles, how can we find the incident angle (latex: \alphaα) at the second air/glass interface knowing the transmitted angle (latex: \theta_tθ t) at the first air/glass boundary? group of answer choices latex: \alpha=\theta_t α = θ t latex: \alpha=90^{\circ}-\theta_t α = 90 ∘ − θ t latex: \alpha=90^{\circ}+\theta_t α = 90 ∘ + θ t latex: \alpha=180^{\circ}-\theta_t

hi there!

your question asks at which segment does freezing occur.

since we're talking about water, the freezing point of water will be 32 degrees fahrenheit or below.

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there are no contact forces mentioned on the list of choices that you've provided.

myth. it was once thought that animals, including cats and dogs, could only see in black and white. however, scientists have proven this to be a myth. in all animals, including humans, the perception of colour is determined by the presence of cells in the eye called cone photoreceptors.

according to jean piaget, in what stage of cognitive development are children able to understand conservation task?

b. preoperational

just took it