Acar with tires of radius 25.0 cm accelerates from rest to 30.0 m/s in 10.0 s. when the car's speed is 2.00 m/s find the linear acceleration of the top of the wheel relative to (a) the center of the wheel, (b) the road. (note that there will be a vertical and horizontal component to the acceleration.

Answer

given,                                    

radius of tire = 25 cm = 0.25 m

initial velocity = 0 m/s                

final velocity = 30 m/s                  

time = 10 s                                        

a) acceleration with respect to center  

   v = u + a t                      

   30 = 0 + 10 a                      

    a = 3 m/s²                            

   radial acceleration            

acceleration w.r.t center of tire =

b) acceleration with respect to road will be equal to 3 m/s²

the order for strong to weak forces such as

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force

the fundamental forces are those forces that act between to objects or element to make interactions. there are four types of fundamental forces such as strong and weak nuclear forces (due to protons and electrons), electromagnetic force (due to the motion of electrons) and gravitational force (due to orbital movement of the planet). if these forces are arranged on the basis of their maximum strength then the order is

strong nuclear force → electromegnetic force → weak nuclear force → gravitational force