In 1985 in san antonio, texas, an entire hotel building was moved several
blocks on 36 dollies. the mass of the building was about 1.45 x 10^6 kg. if
1.00 x 10² mj of work was done to overcome the force of resistance that
was just 2.00 percent of the buildings weight, how far was the building
moved?

The building was moved to a distance of, S = 510.2 m

Explanation:

Given data,

The mass of the building, m = 1.45 x 10⁶ kg

The work done to overcome the force of resistance, E = 1 x 10⁸ J

The force of resistance of the building, 2% of building weight

                                          Fₓ =  2 x 1.45 x 10⁶ x 9.8 / 100

                                               = 284200 N

The work done on the building,

                                    E = Fₓ · S

∴                                   S = E /  Fₓ

                                        = 1.45 x 10⁶ / 284200 N

                                        = 510.2 m

Hence, the building was moved to a distance of, S = 510.2 m

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.