Given: g = 6.67259 × 10−11 n m2 /kg2 . a 438 kg geosynchronous satellite orbits a planet similar to earth at a radius 1.94 × 105 km from the planet’s center. its angular speed at this radius is the same as the rotational speed of the earth, and so they appear stationary in the sky. that is, the period of the satellite is 24 h . what is the force acting on this satellite? answer in units of n.

449.37412 N

Explanation:

G = Gravitational constant = 6.67259 × 10⁻¹¹ m³/kgs²

m = Mass of satellite = 438 kg

M = Mass of planet

T = Time period of the satellite = 24 h

r = Radius of planet =

The time period of the satellite is given by

The gravitational force is given by

The force acting on this satellite is 449.37412 N

im sorry i dont know

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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