Movies and tv shows sometimes portray a person being thrown backwards a sizable distance as a result of being struck by a bullet. calculate the maximum distance that a 70.0-kg object would fly backwards if it is struck by a 10.0-gram projectile moving with a velocity 355 m/s which then completely embeds itself in the object. assume that the angle of this perfectly inelastic collision is such that the combined mass is launched at an angle of 45 degrees above the horizontal, and neglect the effects of air resistance. based on this calculation, evaluate the realism (or lack thereof) of the tv/movie portrayal.

    5.5 n======    assuming that      we have      m = 0.145 kg    a = 38 m/s²therefore    5.51 n, but two significant figures.final answer: 5.5 n

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge