A4000 kg satellite is placed 2.60 x 10^6 m above the surface of the earth.

a) find the acceleration of gravity (g) at 2.60 x 10^6 m above the earth.

b) find the critical velocity to maintain a circular orbit at 2.60 x 10^6 m above the surface of earth. (in both m/sec & km/hr)

c) find the period of the orbit.

d) how many orbits will the satellite make in one day?

e) find the escape velocity for a satellite to leave this orbit and escape the gravitational pull of the earth.

f) find the escape velocity for a rocket leaving the surface of the earth.

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To compare speeds speeds of wagons we will use second newton's law. it states: f = m * ahere we can see that force depends on the acceleration. if we know acceleration for both wagons we can compare them to make conclusion of speeds of wagons.we have: m1 = 10lbm2 = 20lbf1 = 2*f2also: m2 = 2*m1for bill we have equation: f1 = m1 * a1for tom we have equation: f2 = m2 * a2after inserting identities we have: 2*f2 =m1 * a1f2 = 2*m1 * a2in order to make conclusions about speeds we will solve these equations for a and find their ratio: a1 = 2f2 / m1a2 = f2 / 2m1a1 / a2 = (2f2/m1) / (f2/2m1)a1 / a2 = (2f2*2m1) / (m1*f2)a1 / a2 = (4f2m1) / (m1f2)a1 / a2 = 4this ratio is bigger than 1 and this means that a1 is greater than a2. a1 is 4 times greater than a2. speed of bill's wagon is 4 times greater than speed of tom's wagon.