Force p is applied to the 67-kg block when it is at rest. determine the magnitude and direction of the friction force exerted by the surface on the block if (a) p = 0, (b) p = 236 n, and (c) p = 370 n. (d) what value of p is required to initiate motion up the incline? the static and kinetic coefficients of friction between the block and the incline are μs = 0.23 and μk = 0.20, respectively. the friction force is positive if up the incline, negative if down the incline.

3is a crest4 is a trough 2 is the amplitude 1 is the wavelength

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

2.77 x 10^-3 its for plato user