Approximately one billion years ago, the moon orbited the earth much closer than it does today. the radius of the orbit was only 24 400 km. the orbital period was only 23 400 s. today, the average radius is 385 000 km; and the present period is 2.36 × 106 s. assuming that the orbit of the moon is circular, calculate the ratio of the speed of the moon in its ancient orbit to the speed that it has today.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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The correct answer should be b let me know if i’m wrong