Aconductor of length 0.8 m carrying a current of 2.5 a is kept in a magnetic field of 0.6 tesla. what is the magnitude of the force experienced by the conductor if it is inclined at an angle 30° to the direction of the magnetic field?

0.6N

Explanation:

To calculate the magnitude of the force experienced by the conductor, we use the formulae

F= BILsintheta

Where B is the magnetic field

I is the current

L is the length

theta is the angle that the conductor made with the magnetic field

Substituting the given parameters into the formulae,

F = (0.6 × 2.5 × 0.8)sin30°

F= 0.6N

it may be wrong but i think its a

d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day