Acord is wrapped around the rim of a solid uniform wheel 0.280m in radius and of mass 8.80kg. a steady horizontal pull of 32n to the right is exerted on the cord, pulling it off tangentially from the wheel. the wheel is mounted on frictionless bearings on a horizontal axle through its center. what is the wheels angular acceleration? what force does the axle apply to the wheel? what torque does the axle apply to the wheel?

Explanation:

Given

radius of wheel

mass of wheel

Force

Moment of Inertia of solid wheel

Torque is given by

Force on the axle is 32 N since there is no linear acceleration of the system

using Third law F=32 N

Torque of the axle applied to the wheel is zero because force of axle imparted at the center of axle

explanation:

newton's third law, for every action there is an equal and opposite reaction.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.