An ice skater is spinning at 5.2 rev/s and has a moment of inertia of 0.32 kg * m2.
calculate the angular momentum, in kilogram meters squared per second, of the ice skater spinning at 5.2 rev/s.
suppose instead he keeps his arms in and allows friction of the ice to slow him to 2.75 rev/s. what is the magnitude of the average torque that was exerted, in n * m, if this takes 12 s?

Explanation:

The angular momentum is given by the moment of inertia, multiplied by the angular speed of the rotating body:

The angular speed is given by:

Now, we calculate the angular momentum:

The average torque is defined as:

is the angular acceleration, which is defined as:

We have to calculate :

Now, we calculate the angular acceleration:

Finally, we can know the average torque:

the answer would be c. motion and direction

i hope this : )