Aphysics student devised the following method of measuring the muzzle velocity of a rifle: she fires a bullet into a 4.648 kg wooden block resting on a horizontal smooth surface, and attached to a spring of spring constant k = 142.7 n/m. the bullet, whose mass is 7.87 g, remains embedded in the wooden block. she measures the maximum distance that the block compresses the spring to be 9.46 cm. what is the initial speed of the bullet?

Initial velocity of the bullet will be 307.63 m /sec

Explanation:

We have given that mass of the bullet 7.87 gram m= 0.00787 kg

Mass of the block M = 4.648 kg

So total mass M+m = 4.648 +0.00787= 4.655 kg

Spring constant k = 142.7

Compression x=9.46 cm = 0.0946 m

Now according to energy conservation

So initial velocity of the bullet will be 307.63 m /sec

volts times amps 6 x 0.5 3w

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)