What is the magnitude of the maximum stress that exists at the tip of an internal crack having a radius of curvature of 4.5 × 10-4 mm (1.772 × 10-5 in.) and a crack length of 3 × 10-2 mm (1.181 × 10-3 in.) when a tensile stress of 160 mpa (23210 psi) is applied?

To develop this problem it is necessary to apply the concepts related to stress.

The calculation of maximum stress by definition is given by

Where,

= Nominal applied tensile stress

a = Length of a surface crack

= Radius of curvature tip of the internal crack

Now we can find the length of a surface crack,

With this value we find now the ratio of

Therefore the magnitud of the stress would be

Therefore the magnitude of the maximum stress is 1847.42Mpa.

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