Anew roller coaster contains a loop-the-loop in which the car and rider are completely upside down. if the radius of the loop is 11.8 m, with what minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top? assume the rider is not strapped to the car.

To solve this problem it is necessary to apply the concepts based on Newton's second law and the Centripetal Force.

That is to say,

Where,

Centripetal Force

Weight Force

Expanding the terms we have to,

Where,

r = Radius

g = Gravity

v = Velocity

Replacing with our values we have

Therefore the minimum speed must the car traverse the loop so that the rider does not fall out while upside down at the top is 10.75m/s

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2

iron would move it is magnetic there is a mag field around the current in the wire