Alight string is wrapped around the outer rim of a solid uniform cylinder of diameter 75.0 cm that can rotate without friction about an axle through its center. a 3.00 kg stone is tied to the free end of the string. when the system is released from rest, you determine that the stone reaches a speed of 3.40 m/s after having fallen 2.40 m. what is the mass of the cylinder?

Since a light string is wrapped around the outer rim of a solid uniform cylinder, the mass of the cylinder is equal to 18.4 kilograms.

Given the following data:

To calculate the mass of the cylinder:

First of all, we would determine the acceleration of the stone by using the the third equation of motion;

Where:

Substituting the given parameters into the formula, we have;

Acceleration, a = 2.41

Next, we would solve for the torque by using the formula:

Torque, T = 22.17 Newton.

In rotational motion, torque is given by the formula:

Mass = 18.4 kilograms

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18.5 kg

Explanation:

Given

diameter

mass of stone

velocity of stone

height fallen

using

Tension of string will Provide Torque to cylinder

where

and

Put value of T

the motion of a pendulum is a classic example of mechanical energy conservation. a pendulum consists of a mass (known as a bob ) attached by a string to a pivot point. as the pendulum moves it sweeps out a circular arc, moving back and forth in a periodic fashion.

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this