If r = 12 cm, m = 310 g, and m = 40 g , find the speed of the block after it has descended 50 cm starting from rest. solve the problem using energy conservation principles. (treat the pulley as a uniform disk.)

Explanation:

While mass is falling downwards there is no frictional loss so here we can use mechanical energy conservation

So change in gravitational potential energy = gain in kinetic energy of the system

for uniform cylinder we will have

now we have

now we have

graphing motion: mastery test

209be

what is the instantaneous acceleration of

the particle at point b?

0 meters/second?

10 meters/second?

12 meters/second?

velocity imetersisecond

15 meters/second?

20

time (seconds)

answer: 0 meters/second^2