Assuming that 1.0g of aspirin dissolves in 450 ml of water at 10o c, how much aspirin would be lost in the 1.4 ml of water added to the reaction mixture if the mixture were at 10o c during the filtration? would this significantly affect the percent yield above?

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

Explanation:

given data

mass of aspirin = 1 g

volume of water = 450 mL

solubility of aspirin temperature = 10° C

volume of water added = 1.4 mL

to find out

how much amount aspirin would be lost

solution

we know the solubility of aspirin is

solubility of aspirin =

solubility of aspirin =    

solubility of aspirin = 2.2 × g/mL

so

we can say

amount of aspirin dissolved =  solubility of aspirin × volume of water added

put here value

amount of aspirin dissolved = 2.2 ×  × 1.4

amount of aspirin dissolved =  3.1 × g

amount of aspirin dissolved = 0.0031 g

so we can say that this is not affect % yield as amount of aspirin lost is very less

i believe the answer is electric potential.

explanation: