Aprojectile returns to its original height 4.08 s after being launched, during which time it travels 76.2 m horizontally. if air resistance can be neglected, what was the projectile's initial speed?

27.35 m/s

Explanation:

Given

Time of Flight of Projectile T=4.08 s

Range of Projectile =76.2 m

Time Of Flight of Projectile is given by

where u=initial Velocity

Launch angle

g=acceleration due to gravity

Range is given by

divide 1 and 2

squaring and adding 3 & 4 we get

i think its c if i'm wrong