An proton-antiproton pair is produced by a 2.20 × 10 3 2.20×103 mev photon. what is the kinetic energy of the antiproton if the kinetic energy of the proton is 161.90 mev? use the following joules-to-electron-volts conversion 1ev = 1.602 × 10-19 j. the rest mass of a proton is 1.67 × 10 − 27 1.67×10−27 kg.

To solve this problem it is necessary to apply the concepts related to Kinetic Energy in Protons as well as mass-energy equivalence.

By definition the energy in a proton would be given by

The mass-energy equivalence is given as,

Here,

c = Speed of light

The energy of the photon is given by,

Replacing with our values,

Therefore we can calculate the kinetic energy of an anti-proton through the energy total, that is,

Therefore the kinetic energy of the antiproton if the kinetic energy of the proton is 161.90 MeV would be 161.5MeV

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explanation:

as we probably am aware that our atmosphere or air have various levels, each level has different gasses, and each gas has another porousness. at the point when the light originates from lower porousness to higher penetrability, it alters its course. with the goal that implies that when the light originates from the moon to the earth, it alters it's course a lot more occasions. it essentially implies that the state of the light piece of the moon is changed on the earth.

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