A3-g bullet is fired horizontally into a 10-kg block of wood suspended by a rope from the ceiling. the block swings in an arc, rising 3 mm above its lowest position. the velocity of the bullet was:

Velocity of the bullet was 800 m/s.

Explanation:

It is given that,

Mass of the block, m₁ = 10 kg

Mass of the bullet, m₂ = 3 g

Height reached by the block, h = 3 mm

Let v is the velocity of the wooden block. Using the conservation of energy to find it as :

v = 0.24 m/s

Let v' is the velocity of the bullet. The momentum of the system remains conserved. It can be calculated as :

v' = 800 m/s

So, the velocity of the bullet was 800 m/s. Hence, this is the required solution.

are there answer choices to this question? this seems like a question where you have options to choose from.

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.