Aperson with a surface area of 1.20 m2, and a skin temperature of 27 oc, is in a room that is at a temperature of 18.8 °c. the emissivity of the skin is 0.895. the stefan-boltzmann constant is 5.67 x 10-8 w/(m2·) how much power (power is the energy per second) is radiated by the person? keep 2 decimal places. b. how much power is absorbed by the person from the surroundings? keep 2 decimal places. c. what is his net power loss? report as a positive value. keep 2 decimal places.
Answers: 3
= Person's temperature = 27+273.15 = 300.15 K
= Room temperature = 18.8+273.15 = 291.95 K
= Emissivity of skin = 0.895
= Stefan-Boltzmann constant = 
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Aperson with a surface area of 1.20 m2, and a skin temperature of 27 oc, is in a room that is at a t...
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