Acopper rod has a length of 1.3 m and a cross-sectional area of 3.6 10-4 m2. one end of the rod is in contact with boiling water and the other with a mixture of ice and water. what is the mass of ice per second that melts? assume that no heat is lost through the side surface of the rod.

To solve the problem it is necessary to apply the concepts related to heat flow,

The heat flux can be defined as

Where,

k = Thermal conductivity

A = Area of cross-sectional area

d = Length of the rod

Temperature difference between the ends of the rod

Thermal conductivity of copper rod

Area of cross section of rod

Temperature difference  

length of rod

Replacing then,

From the definition of heat flow we know that this is also equivalent

Where,

Mass per second

Latent heat of fusion of ice

Re-arrange to find

Therefore the mass of ice per second that melts is 0.032g

where are the vectors ?