For fully developed laminar pipe flow in a circular pipe, the velocity profile is given by u(r) = 2 (1 - r2/r2) in m/s, where r is the inner radius of the pipe. assuming that the pipe diameter is 3.1 cm, find the (a) maximum and (b) average velocities in the pipe as well as (c) the volume flow rate.

a)Uo= 2 m/s

b)

c)Q=7.54  x 10⁻⁴ m³/s

Explanation:

Given that

Diameter ,D= 3.1 cm

Radius ,R= 1.55 cm

We know that in the pipe flow the general equation for laminar fully developed flow given as

Uo=Maximum velocity

Therefore maximum velocity

Uo= 2 m/s

The average velocity

The volume flow rate

Q=0.000754 m³/s

Q=7.54  x 10⁻⁴ m³/s

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

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