You come across an open container that is filled with two liquids. since the two liquids have different densities, there is a distinct separation between them. water, which has a density of rho w = 1.00 × 10 3 kg/m 3 , fills the lower portion of the container to a depth of 0.221 m . the fluid that is floating on top of the water is 0.335 m deep. if the absolute pressure on the bottom of the container is 1.049 × 10 5 pa , what is the density, rho l , of the unknown fluid? the acceleration due to gravity is g = 9.81 m/s 2 and atmospheric pressure is p 0 = 1.013 × 10 5 pa .

496.57492 kg/m³

Explanation:

= Atmospheric pressure = 101300 Pa

= Density of water =

= Height of water = 0.221 m

= Height of fluid = 0.335 m

g = Acceleration due to gravity = 9.81 m/s²

= Density of the unknown fluid

Absolute pressure at the bottom

The density of the unknown fluid is 496.57492 kg/m³

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.