How much heat must be removed from 456 g of water at 25.0°c to change it into ice at - 10.0°c ? the specific heat of ice is 2090 j/(kg. k) and the latent heat of fusion of water is 33.5 x 10^4 j/kg .

209.98 kJ

Explanation:

mass of water

Initial Temperature of Water

Final Temperature of water

specific heat of ice

Latent heat

specific heat of water

Heat require to convert water at to

Heat require to convert water at to ice at

heat require to convert ice at

Total heat

this is a good question! i'll do some research and come back when i have the answer!

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .