Fr = 12 cm, m = 360 g, and m = 70 g (below), find the speed of the block after it has descended 50 cm starting from rest. solve the problem using energy conservation principles. (treat the pulley as a uniform disk.) solve the problem using energy conservation principles. (b) repeat (a) with r = 5.0 cm.

The speed of the block is 1.65 m/s.

Explanation:

Given that,

Radius = 12 cm

Mass  of pulley= 360 g

Mass of block = 70 g

Distance = 50 cm

(a). We need to calculate the speed

Using energy conservation

Put the value into the formula

(b), We need to calculate the  speed of the block

When r = 5.0 cm

Here, The speed of the block is independent of radius of pulley.

Hence, The speed of the block is 1.65 m/s.

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