A60\ w60 w light bulb (normally ran at 115\ v115 v) is attached to a transformer. the voltage source in the transformer is 35\ v35 v and n_p = 25n p =25. how many turns does the secondary coil need to be to run this lightbulb at 100\ w100 w?

137 turns

Explanation:

The light is rated 60 W and normally operated at 115V,

using electrical power formula;

P (power) = I (currents in Ampere) × V ( potential difference in Volts)

substitute the power and V mentioned above into the formula

60 = I × 115

I = 60 / 115 = 0.522 A

with the Current above we can calculate the voltage expected for 100W in the secondary coil

P = I × V

100 = 0.522 × V

V = 100 ÷ 0.522 = 191.6 Volts is the voltage expected by the secondary coil of the transformer to deliver

using transformer formula with Vs being Voltage in the secondary coil and Vp voltage in primary coil, Ns being number of turns in the secondary coil and Np number of turns in the primary coil.

Vs = 191.6 volts, Vp = 35 volts Np = 25 and Np= ?

Vp/ Vs = Np / Ns

make Ns subject of the formula

Ns = Vs × Np / Vp

Ns = 25 × 191.6 / 35 = 136.9 turns approx 137 turns

32: from largest to smallest, this hierarchy includes eons, eras, periods, epochs, and ages.

33: answer is c

i really hope this answer you out! it makes my day people like you and giving back to the community that has me through school! if you could do me a favor, if this you and this is the very best answer and you understand that all of my answers are legit and top notch. mark as brainliest! and have a awesome day!

another example of kinetic energy would be,

kinetic energy   >     moving energy

answer   >   letter choice (c),   a hammer falling off a table.

hope that !                                         : )