Two identical loudspeakers are placed on a wall 1.00 m apart. a listener stands 4.00 m from the wall directly in front of one of the speakers. a single oscillator is driving the speakers at a frequency of 300 hz.

The phase difference is 0.659 rad.

Explanation:

Given that,

Distance between two identical loudspeakers d= 1.00  m

Distance between speakers and listener r= 4.00 m

Frequency = 300 Hz

Suppose we need to find the phase difference in radian between the waves from the speakers when they reach the observer

We need to calculate the r'

Using Pythagorean theorem

Where, d = distance between two identical loudspeakers

r = distance between speakers and listener

Put the value into the formula

We need to calculate the path difference

Using formula of path difference

We need to calculate the wavelength

Using formula of wavelength

Where, v = speed of sound

f = frequency

Put the value into the formula

We need to calculate the phase difference

Using formula of phase difference

Hence, The phase difference is 0.659 rad.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27

b. a lightning bug, plug of grass, and a worm