A1.0-kg block of aluminum is at a temperature of 50 celsius. how much thermal energy will it lose when it’s temperature is reduced by half?

The lose of thermal energy is, Q = 22500 J

Explanation:

Given data,

The mass of aluminium block, m = 1.0 kg

The initial temperature of block, T = 50° C

The final temperature of the block, T' = 25° C

The change in temperature, ΔT = 50° C - 25° C

                                                     = 25° C

The specific heat capacity of aluminium, c = 900  J/kg°C

The formula for thermal energy,

                             Q = mcΔT

                                 = 1.0 x 900 x 25

                                 = 22500 J

Hence, the lose of thermal energy is, Q = 22500 J

this means that the temperature of both substances will be equal

iron would move it is magnetic there is a mag field around the current in the wire