At time t = 0 s, a wheel has an angular displacement of zero radians and an angular velocity of +26 rad/s. the wheel has a constant acceleration of -0.43 rad/s2. in this situation, the time t (after t = 0 s), at which the kinetic energy of the wheel is twice the initial value, is closest

150s how do you solve for this? ? i keep getting a negative time value

t= 25.04 s

Explanation:

Given  that

Initial angular speed ,ωi= 26 rad/s

Angular acceleration ,α=0.43 rad/s²

We know that kinetic energy of the wheel given as

I=Mass monent of inertia

ω=Angular speed

If kinetic energy is two time then the final angular speed

We know that

t= 25.04 s

After 25.04 s then kinetic energy will become two times of the initial kinetic energy.

the entire statement is true and correct.  

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