Asinusoidally oscillating current with an amplitude of 5.55 a and a frequency of 359 cycles per second is carried by a long, straight wire. a rectangular loop of copper wire with dimensions =72.2 cm by c=32.5 cm is located =80.2 cm from the straight wire, and is coplanar with it. calculate the average power pavg dissipated by the loop if its resistance is 54.3 ω.

Solution:

As per the question:

Current, I(t) = 5.55 A

Frequency, f = 359 Hz

B = 72.2 cm

c = 32.5 cm

a = 80.2 cm

Resistance, R = 54.3

Now,

Th magnetic flux of the loop is given by:

Now,

I(t) =

Now, the magnitude of the induced emf is given by:

The rms value of the induced emf is given by:

Substituting appropriate values in the above eqn:

Now,

To calculate average power:

yup its correct its: c) b b

answer: option c.

explanation: