The force required to stretch a hooke’s-law spring varies from 0 n to 20.2 n as we stretch the spring by moving one end 5.39 cm from its unstressed position. find the force constant of the spring. answer in units of n/m. 014 (part 2 of 2) 10.0 points find the work done in stretching the spring.

The force constant of the spring is 374.77N/m

The workdone in stretching the spring is 0.54439Joules

According to Hooke's law, the force applied to the spring is directly proportional to its extension. This is expressed as:

F = ke

k is the spring constant/Force constant

e is the extension

F is the applied force

Given the following parameters

F = 20.2N

e = 5.39cm = 0.0539m

Get the force constant

k = F/e

k = 20.2/0.0539

k = 374.77N/m

The force constant of the spring is 374.77N/m

Next is to get the workdone on the spring

Work done = 1/2ke²

W = 1/2 * 374.77 * 0.0539²

W = 0.54439

Hence the workdone in stretching the spring is 0.54439Joules

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Explanation:

Given

Force changes from 0 N to 20.2 N

Extension in spring is x=5.39 cm

we know Force applied to stretch spring is given by

(b)Work Done to Stretch it

freezing

deposition

condensation

explanation;

melting also called fusion is the process where solid becomes liquid, sublimation is the process where solid becomes gaseous without first changing to liquid, deposition involves change from gaseous to solid state, freezing involves change from liquid to solid, boiling or evaporation involves change of liquid to gaseous state, while condensation is the change from gaseous state to liquid state.

endothermic reactions involves absorption of heat from the surroundings or the environment while exothermic reactions involves loss of heat energy to the surroundings.

in this case, sublimation, evaporation and melting are endothermic reactions (gain energy from the environment) while, freezing, deposition and condensation are exothermic (loss of energy to the surroundings) reactions.