Apan of water is placed on the stove and heated. the initial temperature of the water is 20 degree celsius. the final temperature is 42. how much energy is required to heat 100 g of water if water has a specific heat of 4.190 j/gk?

Q = 9218 J

Explanation:

Given that

Initial temperature = 20° C

The final temperature = 42°C

Change in the temperature ,ΔT = 42 - 20 = 22°C

m = 100 g

Specific heat ,Cp= 4.190 J/gK

The energy required given as

Q= m Cp ΔT

Now by putting the values in the above equation

Q= 100 x 4.19 x 22

Q = 9218 J

Therefore the energy required is 9218 J.

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