Aheat pump absorbs heat from the atmosphere at a rate of 30 kw. if work is being done to run this heat pump at a rate of 7.7 kw, what is the coefficient of performance (cop) of the heat pump? a) 2.9b) 22c) 0.26d) 3.9e) 4.9

Option D 3.9

Explanation:

First, you need to use the correct equation which is the following:

COP = Q/W

Where:

Q = heat absorbed

W = work done by the pump

COP = coefficient of perfomance

We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:

COP = 30 / 7.7

COP = 3.896

This result you can round it to 3.9. option D.

gans

explanation:

vestigial organs (like your appendix) are organs that no longer serve a purpose.

it is the second option.