The normal boiling point (that is, at p = 1 atm) of mercury is t = 630 k. at this pressure and temperature, mercury vapor may be treated as a monatomic ideal gas. the latent heat of vaporization is l = 5.93 × 1011 erg mole-1. the atomic weight of mercury is 200.6 amu. (a) suppose that the latent heat of vaporization is constant, that mercury vapor may be treated as an ideal gas over the range of interest, and that the specific volume of liquid mercury is negligible compared with the specific volume of mercury vapor. estimate the vapor pressure of mercury at t = 300 k (roughly room temperature). (b) what is the entropy of the liquid at 630 k? hint: you may need to know the entropy of the vapor. in case you don’t remember the expression, you might want to work it out. note that the number of states in d3r and d3p is dn = d3r d3p/(2πℏ)3. you should also remember that for large n , ln n! → n ln n − n .