Aparticle has a de broglie wavelength of 2.1 × 10-10m. then its kinetic energy increases by a factor of 3. what is the particle's new de broglie wavelength, assuming that relativistic effects can be ignored?

Explanation:

given,

de broglie wavelength of the particle = 2.1 × 10⁻¹⁰m

Kinetic energy increase factor = 3

de broglie  wavelength of new particle = ?

we know,

Kinetic energy

...........(1)

Kinetic energy of other particle

............(2)

dividing equation (1)/(2)

i think the answer is b

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer