In a playground there is a small merry-go-round of radius 1.25 m and mass 175 kg. assume the merry-go-round to be a uniform disc. a child of mass 45 kg runs at a speed of 3.0 m/s tangent to the rim of the merry-go-round (initially at rest) and jumps on. if we neglect function. what is the angular speed of the many-go- round after the child has jumped on and is standing at its outer rim?

ωf = 0.82 rad/s

Explanation:

By conservation of the angular momentum:

Where is the inertia of the child, is the inertia of the merry-go-round.

Solving for ωf:

yeet youwelcome broo

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.