It takes 4.57 j of work to stretch a hooke’s-law spring 9.11 cm from its unstressed length. how much the extra work is required to stretch it an additional 9.54 cm? answer in units of j

Explanation:

Given that,

Work done, W = 4.57 J

Distance,

Distance,

We know that the work done by the spring is given by :

k = 550.65 N/m

To find,

Let is the extra work is required to stretch it an additional 9.54 cm. It can be calculated as :

W = 2207.96 J

So, the extra wok done is 2207.96 J.

v=ir = 3x15 =45 v

it breaks and dirupture other materials and other sencews from the bottom